Question

Identify the product of reforming reaction of n-hexane in the presence of \(\text{V}_2\text{O}_5\) over alumina.

• A. Benzene
• B. Cyclohexane
• C. Methyl benzene
• D. Phenol

Hint:

Reforming of n-hexane over a metal oxide catalyst gives an aromatic ring.

Answer 1

The Correct Option is A

Step 1: Recognise the process:
Hexane plus a metal oxide catalyst on alumina at high temperature and pressure is the textbook route to benzene, called aromatisation or reforming.

Step 2: Atom bookkeeping:
$C_6H_{14}$ loses four $H_2$ molecules to give $C_6H_6$. The carbon count stays six, which rules out toluene. No oxygen enters, which rules out phenol.

Step 3: Pick:
Benzene.

Final Answer:
Six carbons are kept, hydrogens are removed, and benzene forms. \[ \boxed{A} \]