Question:easy
Identify the product obtained when 2-chlorobutane is heated with aqueous solution of potassium hydroxide.
Identify the product obtained when 2-chlorobutane is heated with aqueous solution of potassium hydroxide.
Show Hint
Aqueous KOH causes substitution; alcoholic KOH causes elimination.
Updated On: Oct 1, 2026
- But - 1 - ene
- But - 2 - ene
- Butan - 1 - ol
- Butan - 2 - ol
Show Solution
The Correct Option is D
Solution and Explanation
Step 1: Solvent decides the path:
Water favours nucleophilic substitution, since hydroxide is strongly hydrated and acts less as a base.
Step 2: Product:
OH takes the place of Cl on the same carbon, giving $\text{CH}_3\text{CH(OH)CH}_2\text{CH}_3$, butan-2-ol (D).
Final Answer:
Butan-2-ol. \[ \boxed{\text{(D)}} \]
Water favours nucleophilic substitution, since hydroxide is strongly hydrated and acts less as a base.
Step 2: Product:
OH takes the place of Cl on the same carbon, giving $\text{CH}_3\text{CH(OH)CH}_2\text{CH}_3$, butan-2-ol (D).
Final Answer:
Butan-2-ol. \[ \boxed{\text{(D)}} \]
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