Topic: Organic Chemistry - Phenols
Step 1: Understanding the Question:
We are examining the electrophilic aromatic substitution of phenol. The reagent is bromine water (\(Br_2\) in \(H_2O\)).
Step 2: Key Formula or Approach:
Phenol is highly reactive due to the \(+R\) effect of the \(-OH\) group. In aqueous media, phenol ionizes to the phenoxide ion, which is even more reactive.
Step 3: Detailed Explanation:
1. The \(-OH\) group is an ortho and para directing activator.
2. In the presence of water (a polar solvent), the activation is so strong that substitution occurs at all available ortho and para positions simultaneously.
3. The reaction involves three moles of bromine:
\[ C_6H_5OH + 3Br_2 \xrightarrow{H_2O} C_6H_2(Br)_3OH + 3HBr \]
4. The product \(2,4,6\)-tribromophenol forms as a distinct white precipitate.
Step 4: Final Answer:
The product is \(2,4,6\)-tribromophenol.