Step 1: Track the electrophilic then nucleophilic steps.
Chlorobenzene + HNO₃/H₂SO₄ → mainly p-nitrochlorobenzene (Cl is o/p-directing, para avoids steric hindrance). The –NO₂ group activates the ring for nucleophilic aromatic substitution: NaOH at 443K replaces Cl with –OH, giving p-nitrophenoxide. Acidification with H₃O⁺ yields 4-nitrophenol.
Step 2: Final Answer:
4-Nitrophenol (option 4).