Identify the inorganic sulphides that are yellow in colour: (A) $ ({NH}_4)_2{S} $
(B) $ {PbS} $
(C) $ {CuS} $
(D) $ {As}_2{S}_3 $
(E) $ {As}_2{S}_5 $
Choose the correct answer from the options given below:

Question

Statement-I : The correct increasing order of bond length among the following is $O_2^+ < O_2 < O_2^- < O_2^{2-}$.
Statement-II : The correct order of number of unpaired electrons is $O_2^{2-} < O_2^+ < O_2^- < O_2$.

Answer 1

To determine which inorganic sulfides are yellow, we will analyze the provided compounds:

$(NH_4)_2S$: Ammonium sulfide is typically colorless to pale yellow in solution, not distinctly yellow.
$PbS$: Lead(II) sulfide is black.
$CuS$: Copper(II) sulfide is black.
$As_2S_3$: Arsenic trisulfide is characterized by its yellow color.
$As_2S_5$: Arsenic pentasulfide is also yellow.

Based on these observations, the yellow inorganic sulfides are $As_2S_3$ and $As_2S_5$. The correct options are therefore:

(D) and (E) only

Identify the inorganic sulphides that are yellow in colour: (A) \( ({NH}_4)_2{S} \)
(B) \( {PbS} \)
(C) \( {CuS} \)
(D) \( {As}_2{S}_3 \)
(E) \( {As}_2{S}_5 \)
Choose the correct answer from the options given below:

Show Hint

The Correct Option is D

Solution and Explanation

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Questions Asked in JEE Main exam

Identify the inorganic sulphides that are yellow in colour: (A) \( ({NH}_4)_2{S} \) (B) \( {PbS} \) (C) \( {CuS} \) (D) \( {As}_2{S}_3 \) (E) \( {As}_2{S}_5 \) Choose the correct answer from the options given below: