Step 1: Block Check
Au ($5d^{10}6s^{1}$), Hg ($5d^{10}6s^{2}$) and W ($5d^{4}6s^{2}$) fill $5d$.
Step 2: Nobelium
No has configuration $[\text{Rn}]5f^{14}7s^{2}$, where the last electron enters $5f$, which is the $(n-2)f$ subshell for $n=7$.
Step 3: Result
Option (D).
Final Answer:
The element is No.
\[ \boxed{\text{(D) }\text{No}} \]