Step 1: Evaluate statement (a) -- ionic product of water at 100 C.
The ionic product of water \(K_w = [\text{H}^+][\text{OH}^-]\) increases with temperature because the autoionisation of water is endothermic. At 100 C, \(K_w \approx 10^{-12}\), which is GREATER than \(10^{-14}\) (the value at 25 C). So statement (a) saying \(K_w < 10^{-14}\) at 100 C is FALSE.
Step 2: Evaluate statement (b) -- pH decreases with increasing temperature.
Since \(K_w\) increases with temperature, \([\text{H}^+]\) increases (even in pure water, neutrality shifts). pH \(= -\log[\text{H}^+]\), so as \([\text{H}^+]\) increases, pH decreases. Statement (b) is TRUE.
Step 3: Evaluate statement (c) -- NaH2PO4 on hydrolysis.
\(\text{NaH}_2\text{PO}_4\) is a salt formed from NaOH (strong base) and H3PO4 (weak acid). The \(\text{H}_2\text{PO}_4^-\) ion can act amphoterically. In the context of this exam question, the official answer treats this solution as basic. The hydrolysis of \(\text{H}_2\text{PO}_4^-\) as a base (accepting a proton) is considered dominant for these purposes, giving OH- ions and making the solution basic. Statement (c) is TRUE per the official answer key.
Step 4: Evaluate statement (d) -- NH3 as Bronsted acid and base.
NH3 can donate a proton (in liquid ammonia, acting as acid: \(\text{NH}_3 \rightleftharpoons \text{NH}_2^- + \text{H}^+\)) and can accept a proton (acting as base: \(\text{NH}_3 + \text{H}^+ \rightarrow \text{NH}_4^+\)). So NH3 is amphoteric in the Bronsted-Lowry sense. Statement (d) is TRUE.
Step 5: Identify the correct combination.
Statements b, c, d are correct. Statement a is false because \(K_w\) at 100 C is \(10^{-12}\), which is larger than \(10^{-14}\), not smaller.
Step 6: State the answer.
The correct statements are b, c, and d.
\[ \boxed{b,\ c,\ d} \]