Step 1: Concept Overview:
The question focuses on the correct experimental procedure for a Mendelian dihybrid cross. This cross investigates the simultaneous inheritance of two traits, demonstrating the Law of Independent Assortment.
Step 2: Detailed Explanation:
Here's a breakdown of the experimental steps:
A. Trait Selection: Begin by selecting two distinct, contrasting traits to study in the parent generation (e.g., pea seed shape and color).
B. Pure-Breeding Cross: Perform a parental (P generation) cross using pure-breeding (homozygous) parents. One parent should be dominant for both traits, the other recessive (e.g., RRYY x rryy).
D. F₁ Gamete Observation: The offspring of the P cross constitute the F₁ generation, all heterozygous for both traits (e.g., RrYy). Self-cross these F₁ individuals. Independent assortment is demonstrated by the F₁ generation producing four gamete types (RY, Ry, rY, ry) in equal proportions. Step D involves generating and understanding these F₁ gametes, which create the F₂ generation.
C. F₂ Phenotypic Ratio Analysis: The self-cross of the F₁ generation yields the F₂ generation. Count the offspring and analyze their phenotypic ratios. Independent assortment predicts an approximate 9:3:3:1 ratio. This analysis serves as the ultimate test of the law.
Step 3: Solution:
The correct experimental order is: Trait Selection (A) \(\rightarrow\) Pure-Breeding Cross (B) \(\rightarrow\) F₁ Observation for next cross (D) \(\rightarrow\) F₂ Analysis (C), corresponding to A, B, D, C.