Step 1: Spot the catalyst clue.
Anhydrous $\text{AlCl}_3$ points to a Friedel-Crafts reaction. The products are acetophenones, which carry an acetyl group.
Step 2: Pick the acylating agent.
To add the $\text{COCH}_3$ group we use acetyl chloride, $\text{CH}_3\text{COCl}$.
Step 3: Confirm.
The acetyl chloride and $\text{AlCl}_3$ make an acylium ion that attaches at the ortho and para spots, giving the two chloroacetophenones.
\[ \boxed{\text{Acetyl chloride}} \]