Exams
Subjects
Classes
Home
Exams
Chemistry
Polymers
identify homopolymer from...
Question:
medium
Identify homopolymer from following.
Show Hint
Logic Tip: The prefix "Poly" followed by a single chemical name (like Poly-ethylene, Poly-propylene, Poly-acrylonitrile) almost always indicates a homopolymer. Trade names or combined names (Buna-S, Glyptal, Nylon-6,6) usually indicate copolymers.
MHT CET - 2023
MHT CET
Updated On:
Apr 28, 2026
Polyacrylonitrile
Glyptal
Polycarbonate
Buna-S
Show Solution
The Correct Option is
A
Solution and Explanation
Download Solution in PDF
Was this answer helpful?
0
Top Questions on Polymers
The decreasing order of reactivity towards dehydrohalogenation (\(E_1\)) reaction of the following compounds is:
VITEEE - 2024
Chemistry
Polymers
View Solution
Which of the following arrangements does not represent the correct order of the property stated against it?
VITEEE - 2024
Chemistry
Polymers
View Solution
An example of thermosetting plastic is:
JEECUP - 2024
Chemistry
Polymers
View Solution
\( F_2C = CF_2 \) is a monomer of:
JEECUP - 2024
Chemistry
Polymers
View Solution
Want to practice more? Try solving extra ecology questions today
View All Questions
Questions Asked in MHT CET exam
Which disease is primarily spread by female Anopheles mosquitoes?
MHT CET - 2024
HIV and AIDS
View Solution
How many ATP molecules are needed as an initial investment in the glycolytic cycle (normal glycolysis)?
MHT CET - 2024
Glycolysis
View Solution
Total genetic content of an organism is called
MHT CET - 2024
Non-Mendelian Genetics
View Solution
Two monkeys off mass 10 kg and 8 kg are moving along a vertical light rope the former climbing up with an acceleration of 2 m/second square while the latter coming down with a uniform velocity of 2 m/sec square find the tension in the rope at the fixed support
MHT CET - 2024
tension
View Solution
Maximize \( z = x + y \) subject to: \[ x + y \leq 10, \quad 3y - 2x \leq 15, \quad x \leq 6, \quad x, y \geq 0. \] Find the maximum value.
MHT CET - 2024
Linear Programming Problem
View Solution