To solve the given problem, we need to identify the compound A when the given reactant undergoes a reaction with sodium amide (NaNH2). We also need to predict the type of reaction.
The given reactant is a bromobenzene derivative with a methoxy group (OCH3) at the para position to bromine.
Reaction Mechanism
The reaction with NaNH2 involves the formation of a benzyne intermediate. Here's a step-by-step explanation:
NaNH2 is a strong base, which leads to the elimination of HBr from the aromatic ring, creating a triple bond, resulting in the formation of a benzyne intermediate.
The methoxy group (OCH3) present on the benzene ring directs the formation of the triple bond to the ortho position of the methoxy group.
The benzyne intermediate is highly reactive and will quickly undergo further reactions, but for this question, we focus on the formation of benzyne itself.
Prediction of Reaction Type
This reaction is classified as an elimination reaction. Specifically, it is a dehydrohalogenation reaction forming benzyne.
Therefore, compound A is a benzyne intermediate, and the reaction is an elimination reaction.
