Question:medium

How much does a watch lose per day, if its hands coincide every 64 minutes? 

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For time-based problems, focus on the discrepancy per cycle, then calculate how it adds up over time.
Updated On: Aug 18, 2026
  • 32 $\frac{8}{11}$ min
  • 36 $\frac{5}{11}$ min
  • 90 min
  • 96 min 

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The Correct Option is A

Solution and Explanation

Step 1: An accurate clock's hands coincide every \( \frac{720}{11} = 65\frac{5}{11} \) minutes.

Step 2: This watch coincides every 64 minutes, so its rate versus a true clock is \( \frac{65\frac{5}{11}}{64} = \frac{45}{44} \).

Step 3: In 1440 true minutes (24 hours), the watch shows \( 1440 \times \frac{45}{44} = 1472\frac{8}{11} \) minutes.

Step 4: The difference is \( 1472\frac{8}{11} - 1440 = 32\frac{8}{11} \) minutes.
\[ \boxed{32\frac{8}{11} \text{ min}} \]
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