CuSO₄ = Cu + S + 4O = 63.5 + 32 + (4 × 16) = 63.5 + 32 + 64 = 159.5 g·mol⁻¹
159.5 g of CuSO₄ contains 63.5 g of Cu.
\(\text{Copper from 100 g CuSO₄} = \dfrac{63.5}{159.5} \times 100 \,\text{g}\)
= \( \dfrac{63.5 \times 100}{159.5} \approx 39.81 \,\text{g} \)
So, approximately 39.8 g of copper can be obtained from 100 g of CuSO₄.