Question:easy

How many values of magnetic quantum number are possible for each value of azimuthal quantum number?

Show Hint

Think of the magnetic quantum number as counting individual orbital boxes in a subshell diagram. An s-subshell ($\ell=0$) has $2(0)+1=1$ box, a p-subshell ($\ell=1$) has $2(1)+1=3$ boxes, and a d-subshell ($\ell=2$) has $2(2)+1=5$ boxes!
Updated On: Jun 11, 2026
  • $n \ell$
  • $2\ell + 1$
  • $n - \ell$
  • $2\ell$
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Recall what each number controls.
The azimuthal number $\ell$ fixes the subshell shape, and the magnetic number $m_\ell$ counts the orientations of that subshell in space.
Step 2: Write the allowed range of $m_\ell$.
For a given $\ell$, the values run as integers from $-\ell$ up to $+\ell$, that is $m_\ell = -\ell, \dots, 0, \dots, +\ell$.
Step 3: Count the negative entries.
The negatives are $-1, -2, \dots, -\ell$, which is exactly $\ell$ values.
Step 4: Count zero and the positives.
There is one zero, and the positives $+1, +2, \dots, +\ell$ give another $\ell$ values.
Step 5: Add them up.
Total $= \ell + 1 + \ell = 2\ell + 1$.
Step 6: Check with a known case.
For the d subshell, $\ell = 2$ gives $2(2)+1 = 5$ orientations, matching the five d orbitals.
\[ \boxed{2\ell + 1 \text{ (option B)}} \]
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