Question:easy

How many license plates can be made if the license plates contain 6 characters out of which the first two characters are distinct digits and the remaining 4 characters are distinct capital letters of the English alphabet?

Show Hint

Whenever repetitions are not allowed and order matters, use permutations: \[ {}^nP_r=\frac{n!}{(n-r)!} \]
Updated On: Jun 16, 2026
  • \(32292000\)
  • \(2080\)
  • \(117\)
  • \(18962\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Split the plate into two parts.
The plate has $6$ slots: the first two must be distinct digits, and the last four must be distinct capital letters. We count each part and multiply.

Step 2: Fill the first digit slot.
There are $10$ digits ($0$ through $9$), so the first digit can be chosen in $10$ ways.

Step 3: Fill the second digit slot.
It must differ from the first, so $9$ choices remain. The two digits together give $10\times9=90$ ways.

Step 4: Fill the four letter slots.
The letters must all be different. The first letter has $26$ choices, the next $25$, then $24$, then $23$.

Step 5: Multiply the letter choices.
$26\times25\times24\times23=358800$.

Step 6: Combine both parts.
Total plates $=90\times358800=32292000$. \[ \boxed{32292000} \]
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