Step 1: Concept Overview:
The variety of gametes an organism produces depends on the number of heterozygous gene pairs in its genotype. Homozygous pairs (e.g., aa, cc, dd) yield only one allele type and do not increase gamete diversity.
Step 2: Formula:
The number of different gamete types is calculated as:
\[ \text{Number of gamete types} = 2^n \]
where \( n \) represents the count of heterozygous gene pairs.
Step 3: Detailed Solution:
1. Identify the genotype: The genotype is aaBbccdd.
2. Count heterozygous pairs (n): Examining each pair:
- aa: Homozygous
- Bb: Heterozygous
- cc: Homozygous
- dd: Homozygous
Only one heterozygous pair exists (Bb), so \( n = 1 \).
3. Calculate gamete number:
Using \( 2^n \) with \( n = 1 \):
\[ \text{Number of gametes} = 2^1 = 2 \]
The two possible gamete types are aBcd and abcd.
Step 4: Answer:
The organism produces 2 different gamete types. Therefore, option (A) is correct.