Question:medium

How many compounds among the following compounds show inductive, mesomeric as well as hyperconjugation effects?
Compounds

Updated On: Jan 13, 2026
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Correct Answer: 4

Solution and Explanation

To identify compounds exhibiting inductive, mesomeric, and hyperconjugation effects, each compound is analyzed:

  1. C6H5CH2OCH3:
    • Inductive Effect: Present (electronegative oxygen).
    • Mesomeric Effect: Present (benzene ring participation in resonance).
    • Hyperconjugation: Absent (no adjacent C-H bonds to a positively charged or double-bonded carbon).
  2. C6H5CH2CH=CH2:
    • Inductive Effect: Present (σ-bond polarization).
    • Mesomeric Effect: Present (benzene ring).
    • Hyperconjugation: Present (adjacent C-H bonds to the double bond).
  3. C6H5CH2CH(NO2)CH3:
    • Inductive Effect: Present (electronegative nitro group).
    • Mesomeric Effect: Absent (nitro group not directly conjugated with the benzene ring).
    • Hyperconjugation: Present (C-H bonds adjacent to the benzene ring).
  4. C6H5CH2CH2Cl:
    • Inductive Effect: Present (electronegative Cl).
    • Mesomeric Effect: Absent (no conjugation with the benzene ring).
    • Hyperconjugation: Not significant.
  5. C6H5NO2:
    • Inductive Effect: Present (nitro group).
    • Mesomeric Effect: Present (nitro group conjugated with benzene).
    • Hyperconjugation: Absent (lacks appropriate hydrogen atoms).
  6. C6H5CH=CHC6H5:
    • Inductive Effect: Present (polarizable π bonds).
    • Mesomeric Effect: Present (both benzene rings contribute).
    • Hyperconjugation: Present (C-H bonds adjacent to double bonds).
  7. C6H5CH(CH3)COCH3:
    • Inductive Effect: Present (CO group).
    • Mesomeric Effect: Present (CO group conjugates with benzene).
    • Hyperconjugation: Present (methyl groups).
  8. C6H11CH3:
    • Inductive Effect: Present (alkyl group polarization).
    • Mesomeric Effect: Absent (cyclohexane ring does not permit conjugation).
    • Hyperconjugation: Present (multiple C-H bonds).

Based on this analysis, the compounds demonstrating all three effects are: C6H5CH2CH=CH2, C6H5CH=CHC6H5, C6H5CH(CH3)COCH3. There are 3 such compounds. This count does not align with the specified range (4, 4), suggesting a potential discrepancy in the expected range.

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