Question:medium

HCF of the numbers 49 and 91 will be :

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If you're stuck, use the long division method: $91 \div 49 = 1$ (rem 42); $49 \div 42 = 1$ (rem 7); $42 \div 7 = 6$ (rem 0). The last divisor (7) is the HCF.
Updated On: Mar 9, 2026
  • 7
  • 9
  • 11
  • 13
Show Solution

The Correct Option is A

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