Question

Half the perimeter of a rectangular garden, whose length is \(4 \) m more than its width is \(36\) m. Find the dimensions of the garden

Answer 1

Let the width of the garden be denoted by \(x\) and the length by \(y.\)

The problem statement provides the following equations:

\(y - x = 4\)………………. (1)

\(y + x = 36\) ……………..(2)

The combined representation of these equations is:

\(y - x = 4\) and \(y + x = 36\)

\(x\)	\(0\)	\(8\)	\(12\)
\(y\)	\(4\)	\(12\)	\(16\)

Considering the equation \(y + x = 36\):

\(x\)	\(0\)	\(36\)	\(16\)
y	\(36\)	\(0\)	\(20\)

The graphic representation of these equations is shown below.

The intersection point of the lines in the figure is observed to be at \((16, 20)\). Thus, the width of the garden is \(16\) m and the length is \(20\) m.