Step 1: Matrix Multiplication Formula. To compute \( AB \), multiply each element of the rows of \( A \) by the corresponding elements of the columns of \( B \) and sum the results. The matrix multiplication is demonstrated as follows: \[ AB = \begin{bmatrix} 1 & 2 \\ 4 & 3 \end{bmatrix} \times \begin{bmatrix} 5 & 9 \\ 0 & 3 \end{bmatrix} \]
Step 2: Perform Multiplication. The calculations are as follows: - First row, first column: \( 1 \times 5 + 2 \times 0 = 5 \) - First row, second column: \( 1 \times 9 + 2 \times 3 = 9 + 6 = 15 \) - Second row, first column: \( 4 \times 5 + 3 \times 0 = 20 \) - Second row, second column: \( 4 \times 9 + 3 \times 3 = 36 + 9 = 45 \) Consequently, the resulting matrix is \( AB = \begin{bmatrix} 32 & 82 \\ 30 & 62 \end{bmatrix} \).
Step 3: Conclusion. The accurate matrix product obtained is \( \begin{bmatrix} 32 & 82 \\ 30 & 62 \end{bmatrix} \). Therefore, the correct option is (A).
Arrange the following steps in the proper sequence concerning the solution of a linear programming problem.
(A) Graph each constraint as though it were binding, i.e., as if held with strict equality
(B) Find the feasible region, the area of the graph that simultaneously satisfies all constraints
(C) Superimpose contours of the objective function on the feasible region to determine the optimal corner of the region
(D) Construct a graph, placing a decision variable on each axis
Choose the correct answer from the options given below:
Match List-I with List-II
\[\begin{array}{|c|c|}\hline \textbf{List-I} & \textbf{List-II} \\ \hline \text{(A) Closed Interval} & (I)\ [a, b] = \{\,x \in \mathbb{R} : a \leq x \leq b\,\} \\ \hline \text{(B) Open Interval} & (II)\ (a, b) = \{\,x \in \mathbb{R} : a < x < b\,\} \\ \hline \text{(C) Unbounded Interval} & (III)\ [a, b) = \{\,x \in \mathbb{R} : a \leq x < b\,\} \\ \hline \text{(D) Half Open Interval} & (IV)\ (a, \infty) = \{\,x \in \mathbb{R} : a < x\,\} \\ \hline \end{array}\]
Choose the correct answer from the options given below: