Question:medium

Given below are two statements: Statement I: The number of species among \(\mathrm{BF_4^-}\), \(\mathrm{SiF_4}\), \(\mathrm{XeF_4}\) and \(\mathrm{SF_4}\), that have unequal E–F bond lengths is three. Here, E is the central atom. Statement II: Among \(\mathrm{O_2^-}\), \(\mathrm{O_2^{2-}}\), \(\mathrm{F_2}\) and \(\mathrm{O_2^+}\), \(\mathrm{O_2^+}\) has the highest bond order. In the light of the above statements, choose the correct answer.

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Molecular symmetry leads to equal bond lengths, while higher bond order implies stronger and shorter bonds.
Updated On: Apr 2, 2026
  • Both Statement I and Statement II are true
  • Statement I is false but Statement II is true
  • Both Statement I and Statement II are false
  • Statement I is true but Statement II is false
Show Solution

The Correct Option is B

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