Question

Given below are two statements:
Statement I: Methane and steam passed over a heated Ni catalyst produces hydrogen gas.
Statement II: Sodium nitrate reacts with NH\(_4\)Cl to give H\(_2\)O and NaCl.

• A. Both the statement I and II are incorrect
• B. Statement I is incorrect but statement II is correct
• C. Statement I is correct but statement II is incorrect
• D. Both the statements I and II are correct

Hint:

The reaction of methane and steam over a nickel catalyst is a classic example of a reforming reaction, where hydrogen gas is generated.

Answer 1

The Correct Option is D

Let's examine each statement separately to determine their correctness.

1. Statement I: Methane and steam passed over a heated Ni catalyst produces hydrogen gas.

This statement describes the Steam-Methane Reforming (SMR) process, which is a principal method for producing hydrogen gas industrially. In this reaction, methane (\(CH_4\)) is reacted with steam (\(H_2O\)) in the presence of a nickel (Ni) catalyst at high temperatures to produce hydrogen gas, carbon monoxide, and a small amount of carbon dioxide. The chemical reaction is as follows:

\(CH_4 + H_2O \rightarrow CO + 3H_2\)

Therefore, Statement I is correct.

1. Statement II: Sodium nitrate reacts with NH\(_4\)Cl to give H\(_2\)O and NaCl.

This statement can be verified by considering the chemical reaction between sodium nitrate (\(NaNO_3\)) and ammonium chloride (\(NH_4Cl\)). The reaction can produce sodium chloride (\(NaCl\)), water (\(H_2O\)), nitrogen (\(N_2\)) gas, and oxygen gas (\(O_2\)). The balanced chemical reaction is:

\(2NaNO_3 + 2NH_4Cl \rightarrow 2NaCl + 2H_2O + N_2 + O_2\)

This indicates that water is indeed one of the products. Thus, Statement II is correct.

In conclusion, both statements are accurate based on the chemical reactions described. Therefore, the correct option is that both the statements I and II are correct.