Question:medium

Given below are two statements.
Assertion (A):
A random sample of size \(25\) is taken, resulting in a sample mean of \(17.45\) and a sample standard deviation of \(3.6\). Assuming \(H_0:
\mu=18,\ H_1:
\mu\neq18\), the standard error calculated is \(0.72\).
Reason (R):
The standard error for hypothesis testing is calculated using \(\frac{s}{\sqrt{n}}\).

Show Hint

Standard error decreases as sample size increases because \(SE=\frac{s}{\sqrt{n}}\).
Updated On: Jun 6, 2026
  • Both (A) and (R) are correct and (R) is the correct explanation of (A)
  • Both (A) and (R) are correct but (R) is not the correct explanation of (A)
  • (A) is correct but (R) is not correct
  • (A) is not correct but (R) is correct
Show Solution

The Correct Option is A

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