Question:medium

Given below are the reactions. Identify the reaction for which \(K_p<K_c\):

Show Hint

If \(\Delta n_g=0\), then \(K_p=K_c\). If \(\Delta n_g<0\), then \(K_p<K_c\).
Updated On: May 4, 2026
  • \(\ce{N2(g)+O2(g)<=>2NO(g)}\)
  • \(\ce{H2O(g)+CO(g)<=>H2(g)+CO2(g)}\)
  • \(\ce{H2(g)+I2(g)<=>2HI(g)}\)
  • \(\ce{N2(g)+3H2(g)<=>2NH3(g)}\)
Show Solution

The Correct Option is D

Solution and Explanation

To determine the reaction for which \( K_p < K_c \), we use the relation:

\( K_p = K_c(RT)^{\Delta n} \)

where \( \Delta n \) is the difference between the number of moles of gaseous products and gaseous reactants.

For \( K_p < K_c \), the value of \( \Delta n \) should be negative.

Analyzing each option:

  1. \( \text{N}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{NO}(g) \)
    • Reactant moles = 2
    • Product moles = 2
    • \( \Delta n = 2 - 2 = 0 \)
  2. \( \text{H}_2\text{O}(g) + \text{CO}(g) \rightleftharpoons \text{H}_2(g) + \text{CO}_2(g) \)
    • Reactant moles = 2
    • Product moles = 2
    • \( \Delta n = 2 - 2 = 0 \)
  3. \( \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \)
    • Reactant moles = 2
    • Product moles = 2
    • \( \Delta n = 2 - 2 = 0 \)
  4. \( \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) \)
    • Reactant moles = 4
    • Product moles = 2
    • \( \Delta n = 2 - 4 = -2 \)

Conclusion:
The reaction for which \( K_p < K_c \) is \( \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) \).

Was this answer helpful?
0