To determine the reaction for which \( K_p < K_c \), we use the relation:
\( K_p = K_c(RT)^{\Delta n} \)
where \( \Delta n \) is the difference between the number of moles of gaseous products and gaseous reactants.
For \( K_p < K_c \), the value of \( \Delta n \) should be negative.
Analyzing each option:
-
\( \text{N}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{NO}(g) \)
- Reactant moles = 2
- Product moles = 2
- \( \Delta n = 2 - 2 = 0 \)
-
\( \text{H}_2\text{O}(g) + \text{CO}(g) \rightleftharpoons \text{H}_2(g) + \text{CO}_2(g) \)
- Reactant moles = 2
- Product moles = 2
- \( \Delta n = 2 - 2 = 0 \)
-
\( \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \)
- Reactant moles = 2
- Product moles = 2
- \( \Delta n = 2 - 2 = 0 \)
-
\( \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) \)
- Reactant moles = 4
- Product moles = 2
- \( \Delta n = 2 - 4 = -2 \)
Conclusion:
The reaction for which \( K_p < K_c \) is
\( \text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g) \).