Given:
First term, a = 729
7th term = 64
Step 1: Find the common ratio (r)
The nth term of a G.P. is given by:
Tn = a rn−1
For the 7th term:
64 = 729 · r6
r6 = 64 / 729
r6 = (26) / (36)
∴ r = 2 / 3
Step 2: Use the formula for the sum of first 7 terms
Sn = a (1 − rn) / (1 − r), r ≠ 1
So,
S7 = 729 (1 − (2/3)7) / (1 − 2/3)
Step 3: Simplify
1 − 2/3 = 1/3
∴
S7 = 729 × 3 × [1 − (2/3)7]
S7 = 2187 [1 − 128/2187]
S7 = 2187 − 128
S7 = 2059
Final Answer:
The sum of the first 7 terms of the G.P. is
S7 = 2059
If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that P2 = (ab) n .