Question:easy

Genomic DNA is digested with Alu I restriction enzyme that is a 4-base pair cutter. Assuming a random distribution of bases in the genome, what is the frequency with which it will cut the DNA?

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For restriction enzymes: \[ \text{Frequency of occurrence of recognition site} = \frac{1}{4^n} \] where \(n\) is the number of base pairs in the recognition sequence. Thus: \[ 4\text{-bp cutter} \rightarrow \frac{1}{256} \] \[ 6\text{-bp cutter} \rightarrow \frac{1}{4096} \] \[ 8\text{-bp cutter} \rightarrow \frac{1}{65536} \] These are commonly asked values in biotechnology and molecular genetics.
Updated On: Jun 11, 2026
  • \(\dfrac{1}{4}\)
  • \(\dfrac{1}{2^4}\)
  • \(\dfrac{1}{256}\)
  • \(\dfrac{1}{1296}\)
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The Correct Option is C

Solution and Explanation

Step 1: Understand what the question asks.
Alu I is a restriction enzyme that recognises and cuts at a specific $4$ base pair sequence. We want how often, on average, this site shows up in a random genome, because that sets how often the enzyme cuts.
Step 2: Set up the probability for one position.
If bases are randomly distributed, each position is equally likely to be $A$, $T$, $G$, or $C$. So the chance that one particular base sits at a given spot is $\dfrac{1}{4}$.
Step 3: Extend to all four positions of the site.
The recognition site is a fixed run of $4$ specific bases. Each must match independently, so we multiply the per-position probabilities together.
Step 4: Do the multiplication.
\[ P = \left(\frac{1}{4}\right)^4 = \frac{1}{4^4} = \frac{1}{256} \]
Step 5: Interpret the number.
A probability of $\dfrac{1}{256}$ means the exact $4$ base sequence appears on average once in every $256$ base pairs, so the enzyme cuts about once per $256$ bp.
Step 6: Eliminate the distractors.
$\dfrac{1}{4}$ is just one base, $\dfrac{1}{2^4} = \dfrac{1}{16}$ wrongly uses $2$ choices per base, and $\dfrac{1}{1296} = \dfrac{1}{6^4}$ wrongly uses $6$ choices. The correct count uses $4$ bases, giving $4^4 = 256$.
\[ \boxed{\frac{1}{256}} \]
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