Question:medium

Gain cross over frequency is the frequency at which _______.

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Remember the two key crossover frequency definitions: 1. Gain Crossover Frequency ($\omega_{gc}$): Frequency where Magnitude = $1$ (or $0\text{ dB}$). 2. Phase Crossover Frequency ($\omega_{pc}$): Frequency where Phase = $-180^\circ$.
Updated On: Jul 4, 2026
  • Phase is zero
  • Magnitude is $0\text{ dB}$
  • Phase is $-180^\circ$
  • Gain is maximum
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The Correct Option is B

Solution and Explanation

Understanding the Concept: The gain crossover frequency ($\omega_{gc}$) is a critical metric used in frequency domain stability analysis to determine a system's relative stability margins (such as the phase margin). It identifies the specific frequency boundary where the open-loop system transfer function magnitude drops to absolute unity.

Step 1: Define the condition mathematically.

By definition, the gain crossover frequency $\omega_{gc}$ is the frequency at which the absolute magnitude of the loop transfer function $G(j\omega)H(j\omega)$ equals exactly 1: \[ |G(j\omega_{gc})H(j\omega_{gc})| = 1 \]

Step 2: Convert to decibel (dB) log-magnitude scale.

To express this condition on a standard logarithmic scale (as used in Bode plots), apply the decibel conversion formula: \[ \text{Gain in dB} = 20 \log_{10} |G(j\omega)H(j\omega)| \] Substitute the unity crossover condition ($|G(j\omega_{gc})H(j\omega_{gc})| = 1$) into this formula: \[ \text{Gain at } \omega_{gc} = 20 \log_{10}(1) \] Since the logarithm of 1 to any base is exactly 0: \[ \text{Gain at } \omega_{gc} = 20 \times 0 = 0\text{ dB} \] Thus, the gain crossover frequency is the specific frequency where the open-loop magnitude curve crosses the $0\text{ dB}$ reference line.
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