To determine which pair of ions is not iso-electronic, we need to understand the term "iso-electronic." Iso-electronic species are atoms, molecules, or ions that have the same number of electrons.
Let's analyze each pair:
- Fe2+ and Mn2+:
- The atomic number of iron (Fe) is 26, so Fe2+ has \(26 - 2 = 24\) electrons.
- The atomic number of manganese (Mn) is 25, so Mn2+ has \(25 - 2 = 23\) electrons.
- Since Fe2+ (24 electrons) and Mn2+ (23 electrons) do not have the same number of electrons, they are not iso-electronic.
- O2− and F−:
- The atomic number of oxygen (O) is 8, so O2− has \(8 + 2 = 10\) electrons.
- The atomic number of fluorine (F) is 9, so F− has \(9 + 1 = 10\) electrons.
- Since both have 10 electrons, they are iso-electronic.
- Na+ and Mg2+:
- The atomic number of sodium (Na) is 11, so Na+ has \(11 - 1 = 10\) electrons.
- The atomic number of magnesium (Mg) is 12, so Mg2+ has \(12 - 2 = 10\) electrons.
- Since both have 10 electrons, they are iso-electronic.
- Mn2+ and Fe3+:
- Mn2+ has already been calculated to have 23 electrons.
- The atomic number of Fe is 26, so Fe3+ has \(26 - 3 = 23\) electrons.
- Since both have 23 electrons, they are iso-electronic.
Conclusion: The pair Fe2+ and Mn2+ is not iso-electronic because they do not have the same number of electrons. Therefore, the correct answer is Fe2+, Mn2+.