To solve this problem, we need to calculate the compression strain for each hollow cylindrical column supporting the structure. We are given the following parameters:
First, calculate the gravitational force (weight) acting on the structure:
F = mg = 50 \times 10^3 \times 9.8 = 4.9 \times 10^5 \,\text{N}
This force is distributed equally among the four columns. Thus, the force on one column is:
F_{\text{column}} = \frac{4.9 \times 10^5}{4} = 1.225 \times 10^5 \,\text{N}
Next, we calculate the cross-sectional area (A) of one cylinder:
A = \pi (R_o^2 - R_i^2) = \pi (1^2 - 0.5^2) = \pi (1 - 0.25) = \pi \times 0.75
A = 0.75 \pi\,\text{m}^2
Now, we calculate the stress in the column:
\text{Stress} = \frac{F_{\text{column}}}{A} = \frac{1.225 \times 10^5}{0.75 \pi} \approx 5.198 \times 10^4 \,\text{Pa}
Finally, we calculate the strain using Young's Modulus:
\text{Strain} = \frac{\text{Stress}}{Y} = \frac{5.198 \times 10^4}{2.0 \times 10^{11}} \approx 2.60 \times 10^{-7}
Therefore, the compression strain of each column is 2.60 \times 10^{-7}, which matches the correct answer provided.
A wire of uniform resistance \(\lambda\) \(\Omega\)/m is bent into a circle of radius r and another piece of wire with length 2r is connected between points A and B (ACB) as shown in figure. The equivalent resistance between points A and B is_______ \(\Omega\).