Step 1: Testing option C directly:
With \(\lambda=6\): vector is \(2\hat i+\hat j-6\hat k\).
Step 2: Dot product check:
\((2)(1)+(1)(4)+(-6)(1)=2+4-6=0\), confirming perpendicularity.
Step 3: Ruling out others:
Any other \(\lambda\) leaves \(6-\lambda\ne 0\), so the dot product is non-zero and the vectors are not perpendicular.
Final Answer:
\[ \boxed{\lambda=6} \]