Step 1: Understanding the Question:
The topic of this question is Semiconductors and Logic Gates.
We need to determine which set of inputs will output a high logic state ($1$) for both terminals connected to the LEDs. Step 2: Key Formula or Approach:
Trace the Boolean logic output for the gates.
An LED glows when the voltage output of its driving gate is high ($1$). Step 3: Detailed Explanation:
Observe the logic diagram:
1. LED-1 is driven directly by an OR gate with inputs $A$ and $B$.
To make LED-1 glow, $A + B$ must be $1$. This occurs if either $A=1$ or $B=1$.
2. LED-2 is connected to an array dependent on inputs $A, B$ and $C$.
By evaluating the logic gates in sequence for Option D ($A=1, B=1, C=0$):
- LED-1 will glow because $1 + 1 = 1$.
- The final gate driving LED-2 yields a logic high specifically when $A$ and $B$ are high and $C$ is pulled low, fitting this exact combination. Step 4: Final Answer:
The correct combination is $A = 1, B = 1, C = 0$.
