The formula for the environmental lapse rate is:
\[
\text{Lapse rate} = \frac{\text{Change in temperature}}{\text{Change in elevation}} = \frac{T_2 - T_1}{H_2 - H_1}
\]
Where:
- \( T_1 = 14.2^\circ C \) and \( T_2 = 16.9^\circ C \) are the temperatures at elevations \( H_1 = 5 \) m and \( H_2 = 325 \) m respectively.
Now, calculate the change in temperature and elevation:
\[
\text{Change in temperature} = T_2 - T_1 = 16.9 - 14.2 = 2.7^\circ C
\]
\[
\text{Change in elevation} = H_2 - H_1 = 325 - 5 = 320 \text{ m}
\]
Now substitute into the formula for lapse rate:
\[
\text{Lapse rate} = \frac{2.7}{320} = 0.0084375 \, \text{°C/m} = 0.84 \, \text{°C/100 m}
\]
Thus, the lapse rate is \( 0.84 \, \text{°C/100 m} \), and the correct answer is (A).