Step 1: Understand the task.
We are given a circuit built from logic gates with three inputs A, B and C and one output Y. For each option we feed in the listed inputs and check whether the output Y matches.
Step 2: Recall how gates work.
An AND gate gives 1 only when all its inputs are 1. An OR gate gives 1 when at least one input is 1. A NOT gate flips the value. We follow the signals through the gates step by step.
Step 3: Trace the signal forward.
Starting from the inputs, we work out the value at the output of each gate, then carry that value into the next gate, until we reach Y.
Step 4: Test the first option.
For $A=B=1, C=0$, the first option claims $Y=0$. Tracing the inputs through the gates of this circuit, the output actually turns out to be 1, so this option does not match.
Step 5: Test the matching option.
For the same inputs $A=B=1, C=0$, the correct output of the circuit is $Y=1$. This agrees with the second option.
Step 6: Confirm the answer.
Only the case stating $A=B=1, C=0 \rightarrow Y=1$ matches the true behaviour of the circuit. \[ \boxed{A=B=1,\ C=0 \rightarrow Y=1} \]