To verify if the function $f(x) = x^3 + 5x + 1$ is one-one and onto, we analyze its derivative for monotonicity: \[f'(x) = 3x^2 + 5\] Because $f'(x) = 3x^2 + 5>0$ for all real numbers $x$, the function $f(x)$ is strictly increasing, which implies it is one-one. Furthermore, due to its strictly increasing nature, the function is also onto $\mathbb{R}$, as it spans all real values. Consequently, the function is both one-one and onto on $\mathbb{R}$.