Question:medium
For an op-amp having a slew rate of \(4 \text{ V}/\mu s\), what is the maximum closed-loop voltage gain that can be used when input signal varies by \(0.1V\) in \(10\mu s\)?
For an op-amp having a slew rate of \(4 \text{ V}/\mu s\), what is the maximum closed-loop voltage gain that can be used when input signal varies by \(0.1V\) in \(10\mu s\)?
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For slew-rate based op-amp questions, always use:
\[
\text{Slew Rate}=A_v\left(\frac{dV_i}{dt}\right)
\]
Thus,
\[
A_v=\frac{\text{Slew Rate}}{dV_i/dt}
\]
The calculated gain gives the maximum value possible without introducing slew-rate distortion.
Updated On: May 22, 2026
- \(40\)
- \(4\)
- \(400\)
- \(4000\)
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The Correct Option is C
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