Question:medium

For a weak base of concentration \(C\) and degree of dissociation \(\alpha\), what is the correct relation between \(K_b\) and \(C\)?

Show Hint

For weak electrolytes (weak acids or weak bases), when the degree of dissociation \(\alpha\) is very small, we use the approximation \(1-\alpha \approx 1\). Thus, the relation becomes: \(K = C\alpha^2\).
Updated On: Apr 23, 2026
  • \(K_b = C\alpha\)
  • \(K_b = C\alpha^2\)
  • \(K_b = \dfrac{\alpha}{C}\)
  • \(K_b = \dfrac{C}{\alpha^2}\)
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
2