Question:medium

For a particle performing S.H.M. the displacement - time graph is shown.
For that particle the force - time graph is correctly shown in graph

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$F \propto -x$: If $x$ is positive, $F$ is negative. If $x$ is at a maximum, $F$ is at a minimum.
Updated On: May 14, 2026
  • (a)
  • (b)
  • (c)
  • (d)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
In Simple Harmonic Motion (S.H.M.), the restoring force is proportional to the negative of displacement.
The shapes of the displacement and force graphs must directly reflect this negative proportionality.
Step 2: Key Formula or Approach:
Equation of S.H.M.: $F = -ky$.
If the displacement graph is $y = A\sin(\omega t)$, then the force graph is $F = -kA\sin(\omega t)$.
Step 3: Detailed Explanation:
The given displacement $y$-$t$ graph is a positive sine wave, which can be mathematically modeled as: \[ y = A\sin(\omega t) \] Using the S.H.M. restoring force equation: \[ F = -ky \] Substitute the displacement $y$: \[ F = -k(A\sin(\omega t)) = -F_{\text{max}}\sin(\omega t) \] This resulting function describes a negative sine wave (an inverted sine wave).
Looking at the options provided in the image: - Graph (a) starts at a negative maximum, representing $-\cos(\omega t)$. - Graph (b) starts at a positive maximum, representing $+\cos(\omega t)$. - Graph (c) starts at zero and initially goes negative, representing $-\sin(\omega t)$. - Graph (d) starts at zero and initially goes positive, representing $+\sin(\omega t)$. Therefore, graph (c) perfectly represents the force.
Step 4: Final Answer:
Graph (c) is the correct representation.
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