Question:medium

For a gas having $X$ degrees of freedom, $\gamma$ is

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Logic Tip: This formula helps calculate the adiabatic constant for monoatomic, diatomic, and polyatomic gases based on their rotational and vibrational freedom.
Updated On: Apr 28, 2026
  • $\frac{1+X}{2}$
  • $1+\frac{X}{2}$
  • $1+\frac{2}{X}$
  • $1+\frac{1}{X}$
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The Correct Option is C

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