Question:medium

For a common emitter transistor, if \(\frac{I_C}{I_E} = 0.95\), then the current gain is

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Relation: \(\beta = \frac{\alpha}{1-\alpha}\)
Updated On: May 14, 2026
  • \(47.5\)
  • \(44\)
  • \(19\)
  • \(15\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
In a transistor, the current gain in common base configuration (\(\alpha\)) is the ratio of collector current to emitter current.
The current gain in common emitter configuration (\(\beta\)) is the ratio of collector current to base current.
These two parameters are mathematically related through the current conservation equation \(I_E = I_B + I_C\).
Step 2: Key Formula or Approach:
The given ratio is \(\alpha = \frac{I_C}{I_E} = 0.95\).
The relation between \(\beta\) and \(\alpha\) is: \[ \beta = \frac{\alpha}{1 - \alpha} \] Step 3: Detailed Explanation:
Substitute the given value of \(\alpha = 0.95\) into the formula for \(\beta\): \[ \beta = \frac{0.95}{1 - 0.95} \] Perform the subtraction in the denominator: \[ \beta = \frac{0.95}{0.05} \] Simplify the fraction by multiplying numerator and denominator by 100: \[ \beta = \frac{95}{5} = 19 \] Thus, the current gain in common emitter configuration is 19.
Step 4: Final Answer:
The current gain of the transistor in common emitter mode is 19.
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