Question:medium

For a chemical reaction $A \rightarrow B$ the rate of the reaction is $2 \times 10^{-3}$ mol dm$^{-3}$ s$^{-1}$ when the initial concentration is 0.05 mol dm$^{-3}$. The rate of the same reaction is $1.6 \times 10^{-2}$ mol dm$^{-3}$ s$^{-1}$ when the initial concentration is 0.1 mol dm$^{-3}$. The order of the reaction is

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If doubling concentration increases rate by 8 times ($2^3$), the order is 3.
Updated On: Apr 10, 2026
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The Correct Option is C

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