Question:hard

Following are the statements pertaining to power in pumps :
(A) The efficiency of any given pump (\(\eta\)) is a ratio defined as the water horsepower out divided by the mechanical horsepower into the pump
(B) No pump can convert all of its mechanical power into water power
(C) Mechanical power is lost in the pumping process due to friction and other physical losses
(D) It is because of these losses that the horsepower going into the pump must be greater than the water horsepower leaving the pump
Choose the correct answer from the options given below:

Show Hint

Remember the power relationship in pumps:
\[ \text{Shaft Power (Input)} = \text{Water Power (Output)} + \text{Losses} \]
Since losses are always positive in any real system, Input Power is always greater than Output Power, and efficiency (\(\eta\)) is always less than 1.0 (100%).
  • (A), (B) and (D) only.
  • (A), (B) and (C) only.
  • (A), (B), (C) and (D) only.
  • (B), (C) and (D) only.
Show Solution

The Correct Option is C

Solution and Explanation

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