Question

Five groups of letters are given. One of these groups is different from the other four. Find the odd one. YDEUZ, ASHBR, OZPEQ, AXCMF, HLXEF

• A. YDEUZ
• B. ASHBR
• C. OZPEQ
• D. AXCMF

Hint:

In odd-one-out letter-group questions, convert letters into their alphabetical positions and look for common patterns such as consecutive letters, equal gaps, symmetry, or reverse-order relationships. The group that breaks the common pattern is the answer.

Answer 1

The Correct Option is D

Step 1: Examine the letter positions. \[ \begin{aligned} \text{YDEUZ} & : 25,\;4,\;5,\;21,\;26 \text{ASHBR} & : 1,\;19,\;8,\;2,\;18 \text{OZPEQ} & : 15,\;26,\;16,\;5,\;17 \text{AXCMF} & : 1,\;24,\;3,\;13,\;6 \text{HLXEF} & : 8,\;12,\;24,\;5,\;6 \end{aligned} \]

Step 2: Look for consecutive alphabet pairs.
• YDEUZ: D(D) and E(5) are consecutive; Y(25) and Z(26) are consecutive.
• ASHBR: A(A) and B(B) are consecutive; S(19) and R(18) are consecutive.
• OZPEQ: O(15), P(16), and Q(17) occur consecutively.
• HLXEF: E(5) and F(6) are consecutive.
• AXCMF: A(A), X(24), C(C), M(13), F(6) contain no pair of consecutive letters.

Step 3: Identify the odd group. All the groups except AXCMF contain at least one pair of consecutive alphabet letters. Therefore, AXCMF is different from the others. \[ {\text{AXCMF}} \] Hence, the correct answer is Option (D).