Step 1: Understanding the Concept
For a number to be divisible by 10, its last digit (units place) must be 0. Since we are forming a 5-digit number without repetition, once 0 is fixed at the end, we arrange the remaining digits in the other places. Step 2: Detailed Calculation
1. Digits available: {0, 1, 2, 3, 4, 5} (Total 6 digits).
2. Constraint (Divisibility by 10): The units place is fixed with the digit '0'. (1 way)
3. Filling the remaining 4 places: - We need to choose and arrange 4 digits from the remaining 5 digits {1, 2, 3, 4, 5}.
- The number of ways to fill the 1st place: 5 options.
- The number of ways to fill the 2nd place: 4 options.
- The number of ways to fill the 3rd place: 3 options.
- The number of ways to fill the 4th place: 2 options.
4. Total Numbers: $5 \times 4 \times 3 \times 2 \times 1 = 120$. Step 3: Final Answer
The number of five-digit numbers divisible by 10 is 120.