Question

Find the value of the trigonometric function \(sin (-\frac{11π}{3}).\)

Answer 1

It is known that the values of tan x repeat after an interval of π or 180°.

\(∴sin(-\frac{11{\pi}}{3})=sin(-\frac{11{\pi}}{3}+2×2{\pi})=sin(\frac{\pi}{3})=\frac{\sqrt3}{2}\)