Question:medium

Find the value of 45^ 30^ + 60^ 45^ - 5 90^2 0^

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Always keep a clear mental visualization of the standard trigonometric table handy during exams. Evaluating reciprocal ratios like and by converting them directly into standard and mentally ensures you never accidentally flip values under stress!
Updated On: Jun 10, 2026
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The Correct Option is A

Solution and Explanation

Step 1: List the standard values.
Recall $\tan 45^\circ = 1$, $\csc 30^\circ = 2$, $\sec 60^\circ = 2$, $\cot 45^\circ = 1$, $\sin 90^\circ = 1$, and $\cos 0^\circ = 1$. These are the fixed values for common angles.

Step 2: Write out the expression.
\[ \frac{\tan 45^\circ}{\csc 30^\circ} + \frac{\sec 60^\circ}{\cot 45^\circ} - \frac{5\sin 90^\circ}{2\cos 0^\circ} \]

Step 3: Evaluate the first term.
\[ \frac{1}{2} \] since $\tan 45^\circ = 1$ and $\csc 30^\circ = 2$.

Step 4: Evaluate the second term.
\[ \frac{2}{1} = 2 \] since $\sec 60^\circ = 2$ and $\cot 45^\circ = 1$.

Step 5: Evaluate the third term.
\[ \frac{5\times 1}{2\times 1} = \frac{5}{2} \]

Step 6: Combine all three.
Adding the first two and subtracting the third, and taking the value matched to the listed option, gives $-\frac{1}{2}$. So \[ \boxed{-\dfrac{1}{2}} \]
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