We are given the diameters of the spheres. The formula for the surface area \( A \) of a sphere is:
\[ A = 4 \pi r^2 \] where \( r \) is the radius of the sphere.
The radius \( r_1 = \frac{14}{2} = 7 \, \text{cm} \). Substituting into the surface area formula: \[ A_1 = 4 \pi (7)^2 = 4 \pi \times 49 = 196 \pi \, \text{cm}^2 \] Using \( \pi = 3.14 \): \[ A_1 = 196 \times 3.14 = 615.44 \, \text{cm}^2 \]
The radius \( r_2 = \frac{21}{2} = 10.5 \, \text{cm} \). Substituting into the surface area formula: \[ A_2 = 4 \pi (10.5)^2 = 4 \pi \times 110.25 = 441 \pi \, \text{cm}^2 \] Using \( \pi = 3.14 \): \[ A_2 = 441 \times 3.14 = 1388.94 \, \text{cm}^2 \]
The radius \( r_3 = \frac{3.5}{2} = 1.75 \, \text{m} \). Substituting into the surface area formula: \[ A_3 = 4 \pi (1.75)^2 = 4 \pi \times 3.0625 = 12.25 \pi \, \text{m}^2 \] Using \( \pi = 3.14 \): \[ A_3 = 12.25 \times 3.14 = 38.465 \, \text{m}^2 \]