The given G.P. is \(x^3,x^5,x^7\), ...
Here, a = \(x^3\) and r = \(x^2\)
Sn = a\(\frac{(1-r^n)}{1-r}\)
= \(\frac{x^3[1-(x^2)^n]}{1-x^2}\)
= \(\frac{x^3(1-x^2n)}{1-x^2}\)
If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that P2 = (ab) n .