Find the sum of the products of the corresponding terms of the sequences
2, 4, 8, 16, 32
and
128, 32, 8, 2, \( \frac{1}{2} \)
Product of corresponding terms:
2 × 128 = 256
4 × 32 = 128
8 × 8 = 64
16 × 2 = 32
32 × \( \frac{1}{2} \) = 16
Sum of the products = 256 + 128 + 64 + 32 + 16
= 496