Step 1: Spot the reaction type:
Conc. H2SO4 with water on an alkene means electrophilic addition of H-OH across the double bond.
Step 2: Choose the carbocation:
The two double-bond carbons are C1 (bearing CH3) and C2 (bearing H). Putting H+ on C2 leaves a tertiary cation on C1. Putting H+ on C1 would leave only a secondary cation on C2. The tertiary cation is more stable because the methyl group donates electrons by the +I effect and by hyperconjugation.
Step 3: Add water:
Water adds to C1, and loss of a proton gives the alcohol with OH and CH3 on C1.
Step 4: Compare the options:
Only the option showing OH and CH3 on the same carbon fits. The option with OH next to CH3 is the unfavoured route, and the CH2OH options change the carbon skeleton, which does not happen here.
Final Answer:
The alcohol is 1-methylcyclohexanol.
\[ \boxed{\text{Option (B)}} \]
