Question:medium

Find the smallest number between 2000 and 3000 that is exactly divisible by 21, 24 and 28.

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For “exactly divisible by several numbers,” take the LCM} and scan multiples within the interval. Multiplying once more than the floor of \(\frac{\text{lower bound}}{\text{LCM}}\) gives the first valid multiple.
Updated On: Nov 25, 2025
  • None of these
  • 2000
  • 2352
  • 2016
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The Correct Option is D

Solution and Explanation

Step 1: Calculate LCM
\(21 = 3 \times 7,\; 24 = 2^3 \times 3,\; 28 = 2^2 \times 7 \;\Rightarrow\; \text{LCM} = 2^3 \times 3 \times 7 = 168.\)

Step 2: Determine the first multiple within [2000,3000]
\(168 \times 11 = 1848 < 2000,\; 168 \times 12 = 2016 \;\Rightarrow\; \text{smallest required number} = 2016.\)

\[\boxed{2016}\]
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